f(2)=3-2(2)^2

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Solution for f(2)=3-2(2)^2 equation: 



f(2)=3-2(2)^2

We move all terms to the left:

f(2)-(3-2(2)^2)=0

We add all the numbers together, and all the variables

f^2+481=0

a = 1; b = 0; c = +481;
Δ = b2-4ac
Δ = 02-4·1·481
Δ = -1924
Delta is less than zero, so there is no solution for the equation

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